Mods pls dont delete i js wanna help

Will reply aaj shaam tk sbke dms ka

this is the list of chapters that are required to score around 150-180 marks in JEE mains.

i have used AI to organise all the three chapters into a single picture. also the chapters are arranged in prerequisite order i.e chapters you need to do first before starting next.

The source is anup daddy, from this video : https://www.youtube.com/live/d6N64-JgdPc?si=lrOwmz6H0OYe74p0&t=4825

Out of context but i genuinely want your opinions as i am lowkey starting to become philosophical 🤖

Study hard guysss

On the scale of 1 to 10 how difficult is this sheet? Are the questions good for mains level? (Magnetism)

I solved pyqs of mec and i found the pyqs to be verrryyy easyy but im taking quite a lot time solving this sheet

Dropper hu rotation 11th me upar upar se kra tha kuch yaad nhi hai . Koi agar ye one shot dekha ho toh review de do ...

Abhi ekdam 0 pe hu, matlab last test sirf 12 (+200) hi aaye the, aur pehle full syllabus test main sirf 60+60+60+60 hi aaye the, is it still possible?

So I am preparing for jee i want to know Abt other exams i can give like wbjee etc

I dunno know Abt other exams

94 days left btw 😈😈☝️☝️☝️

PW ab netflex banna chata ha. wtf bhai its so annoying

PW enhancer extention wale bhaiya plz fix this🙏🙏

I m js a dude who's cooked cz of online + dummy (in 11th rn) so it's quite lonely atp :( js dm me if some1s interested in yapping shi 😁

Hi everyone, I wanted to share a mathematical relationship I derived regarding the coordinates of a parabola's vertex, which I call the Kumar Theorem of Balanced Vertices. This theorem establishes the exact algebraic condition required to constrain the vertex of a vertical parabola to the identity lines y = x or y = -x.

Let a standard vertical parabola be defined by the quadratic equation:

y = ax^2 + bx + c

The x-coordinate of the vertex represents the axis of symmetry and the average value of any two symmetric points on a horizontal line intersecting the curve. This is given by the formula:

x_avg = -b / 2a

The Kumar Theorem of Balanced Vertices states that if we impose the strict geometric constraint where the magnitude of the y-coordinate at the vertex equals the value of this average axis of symmetry (y_vertex = ± x_avg), the vertex is forced to balance perfectly on the lines y = x or y = -x.

We can derive this using the standard formula for the vertex y-coordinate:

y_vertex = (4ac - b^2) / 4a

Applying the theorem's condition (y_vertex = ± x_avg), we set them equal to each other:

(4ac - b^2) / 4a = ± (-b / 2a)

To simplify the expression, we can multiply the right side by 2/2 to establish a common denominator:

(4ac - b^2) / 4a = ∓ 2b / 4a

Since the denominators are now identical on both sides, we can eliminate them completely:

4ac - b^2 = ∓ 2b

Rearranging the terms to isolate the c variable gives:

4ac = b^2 ∓ 2b

Finally, solving explicitly for the constant c yields the final formula for the theorem:

c = (b^2 ± 2b) / 4a

In conclusion, according to the Kumar Theorem of Balanced Vertices, for any vertical parabola where you choose the coefficients 'a' and 'b', this single consolidated formula calculates the precise value of 'c' needed to lock the vertex exactly onto the diagonal identity lines.

I would love to hear your thoughts on this derivation or if this specific constraint is utilized under a different name in advanced coordinate geometry frameworks!

So mai 11th class ka student hu and is year ke starting se hi Maine bohot acchi mehnat ni ki thi like I was not serious at all pura chhutti ka din barbad karta tha but finally I'll stop this to mai abhi physics padh raha hu and I need to know ki questions mai kaise karu like pura chapter padhne ke baad ya phir topic wise. Please help. Any other tips are welcome too.

Free wali to dm kardo pls

I've been giving tests regularly marks bhi theek thaak aa rahe hai but confidence kaise aayega 😟

Kya karu yawr darr orr lag raha hai JEE paas aa raha hai 💔

https://gluansinha-star.github.io/sunrise-countdown/

no login needed as it saves in your cookies

its deployed here , you can see the preview in the preview section and change the start and end date in set date section

"i didnt do anything for 2 years but now i understand i fucked up, now i am going to lock in and study 15 hours a day, is iit bombay possible?" lmao

haven't slept since yesterday, ate twice, didn't do any workout, didn't journal, didn't go out
didn't draw
I should be posting this on the header instead of the timer

I'm thinking of going to dusserha fair tmrw, family's gonna poke me anyway so I'm in.
It's hard to live with momma sometimes.

My mental health has taken a big toll lately, it's as bad as it was in february
or worse
I don't have the means to get anything checked or worked for

I've made some friends 'round here I should stop with all the whining I do, it's annoying and embarrassing.

Last time I went out I had a good time let's hope tomorrow goes good.

I was thinking "I say best of luck to everyone but I don't want these people to get any wishes, I want the best for me not for someone else" that was a fleeting unkind thought but I haven't stopped coming back to it.

my best wishes to all
Gute Nacht <3

I didn't touch physics Idk shiii and m so scared please help me I wanna be in like bits goa is this series good for like first time????

Pehli baat hatho se kuch banaya h

boree ho ra tha